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Exam Code: 6V0-21.25 Dumps

Questions and Answers: 104

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NEW QUESTION: 1
Which three features does Cisco CX provide? (Choose three.)
A. Category or reputation-based URL filtering
B. VPN authentication
C. Email virus scanning
D. Application optimization and acceleration
E. Application Visibility and Control
F. HTTPS traffic decryption and inspection
Answer: A,E,F

NEW QUESTION: 2
Which two statements are true regarding lot-based unit of measure (UOM) conversions? (Choose two.)
A. Updating the on-hand balance on a lot-based UOM conversion requires a cycle count transaction with the lot number provided in the count record.
B. You cannot create lot-specific UOM conversions for on-hand lots or lots with a zero balance.
C. During a PO receipt, the lot-based conversion cannot be updated if the lot does not match existing conversion rates.
D. You cannot update existing on-hand balances for lot-based UOM conversions.
E. You can create lot-specific UOM conversions for on-hand lots or lots with a zero balance.
Answer: C,E

NEW QUESTION: 3
A 50-year-old depressed client has recently lost his job. He has been reluctant to leave his hospital room. Nursing care would include:
A. Providing sensory stimulation
B. Monitoring elimination patterns
C. Forcing the client to attend all unit activities
D. Encouraging the client to discuss why he is so sad
Answer: B
Explanation:
(A) The client should be encouraged to attend the unit activities. The nurse and client should choose a few activities for the client to attend that will be positive experiences for him. (B) The nurse should encourage the client to discuss his feelings and to begin to deal with the depression. (C) Depressed persons often have little appetite and poor fluid intake. Constipation is common. (D) A calm, consistent level of stimuli is most effective. Sensory deprivation and overstimulation should be avoided.

NEW QUESTION: 4

Which code fragment, when inserted at line n1, produces the result fy20`4.txt?
A. stream<path> files =Files.find(paths. get("D\\ report") , (p, a) -> a isRagular File ());
B. stream<path> files = Files. Walk. get("D\\ report"), 3, (p, a) -> p.isregularFile()) ;
C. stream<path> files = Files.find(paths. get("D\\ report"\\ry2014.txt")) '
D. stream<path> files = Files. Walk. get("D\\ report");
Answer: D


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