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NEW QUESTION: 1
同等クラスのテストに関して、次のうちどれが正しいですか？
A. 通信プロトコルとグラフィカルユーザーインターフェイスのテストに役立ちます。
B. そのパーティションの代表的な値を1つだけ考慮することで、パーティション全体をカバーできます。
C. テスト入力は、指定された機能仕様の派生境界から取得されます。
D. 関数に実装されたプロセスのステートレスな振る舞いが特徴です。
Answer: B
NEW QUESTION: 2
Gill has written the following LotusScript Web service class: Class GetNum Private i As Integer Public Sub New(i As Integer) Me.i = i End Sub Public Function getInt() As Integer getInt = i End Function End Class He has set the PortType class properly, but he keeps getting an error when he tries to save the Web service. Why is he getting the error?
A. BecauseLotusScript Web services aren't allowed to have a "New" sub
B. BecauseLotusScript Web services aren't allowed to have a "New" sub with parameters
C. Because the Class was not defined to be "Public"
D. Because the "Me" statement is not valid within Web service code
Answer: B
NEW QUESTION: 3
You need to create a simple, holistic check for your system's general availablity and uptime. Your system presents itself as an HTTP-speaking API. What is the most simple tool on AWS to achieve this with?
A. EC2 Health Checks
B. CloudWatch Health Checks
C. Route53 Health Checks
D. AWS ELB Health Checks
Answer: C
Explanation:
You can create a health check that will run into perpetuity using Route53, in one API call, which will ping your service via HTTP every 10 or 30 seconds.
Amazon Route 53 must be able to establish a TCP connection with the endpoint within four seconds. In addition, the endpoint must respond with an HTTP status code of 200 or greater and less than 400 within two seconds after connecting.
http://docs.aws.amazon.com/Route53/latest/DeveloperGuide/dns-failover-determining-health-of- endpoint s.html
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