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Exam Code: AD0-E716 Dumps

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NEW QUESTION: 1
기능적 승인이 사용됩니다.
A. IS 부서를 기능적으로 설명합니다.
B. 응용 소프트웨어의 기능적 설명.
C. 사용자 역할 및 책임을 문서화합니다.
D. EDI 트랜잭션에 대한 감사 추적으로서.
Answer: D
Explanation:
설명:
기능 승인은 전자 파트너가 전자 문서를 받았음을 알려주는 표준 EDI 트랜잭션입니다. 다양한 유형의 기능 수신 확인은 다양한 수준의 세부 정보를 제공하므로 EDI 트랜잭션에 대한 감사 추적 기능을 수행 할 수 있습니다. 다른 선택 사항은 기능 수신 확인의 설명과 관련이 없습니다.

NEW QUESTION: 2
There are three servers in the pool: 172.16.20.1, 172.16.20.2, and 172.16.20.3, with the virtual IP address
10.0.20.88.
A user CANNOT connect to an HTTP application. To understand the problem and find a solution, the LTM Specialist runs two concurrent traces on the LTM device, with the following results:
Trace on client side:
tcpdump: verbose output suppressed, use -v or -vv for full protocol decode listening on 0.0, link-type EN10MB (Ethernet), capture size 96 bytes
22:22:07.423759 IP 172.16.20.100.53875 > 10.0.20.88.80: S 998346084:998346084(0) win 5840 <mss
1460,sackOK,timestamp 67942058 0,nop,wscale 4>
22:22:07.424056 IP 10.0.20.88.80 > 172.16.20.100.53875: S 4671780:4671780(0) ack 998346085 win
4380 <mss 1460,nop,wscale 0,nop,nop,timestamp 2392362490 67942058,sackOK,eol>
22:22:07.424776 IP 172.16.20.100.53875 > 10.0.20.88.80: . ack 1 win 365 <nop,nop,timestamp 67942058
2392362490>
22:22:07.424790 IP 172.16.20.100.53875 > 10.0.20.88.80: P 1:149(148) ack 1 win 365
<nop,nop,timestamp 67942058 2392362490>
22:22:07.424891 IP 10.0.20.88.80 > 172.16.20.100.53875: . ack 149 win 4528 <nop,nop,timestamp
2392362491 67942058>
22:22:12.024850 IP 10.0.20.88.80 > 172.16.20.100.53875: R 1:1(0) ack 149 win 4528
6 packets captured
6 packets received by filter
0 packets dropped by kernel
Trace on server side:
tcpdump: verbose output suppressed, use -v or -vv for full protocol decode listening on internal, link-type EN10MB (Ethernet), capture size 96 bytes
22:22:07.424881 IP 172.16.20.100.53875 > 172.16.20.2.80: S 51116678:51116678(0) win 4380 <mss
1460,nop,wscale 0,nop,nop,timestamp 2392362491 0,sackOK,eol>
22:22:08.424893 IP 172.16.20.100.53875 > 172.16.20.2.80: S 51116678:51116678(0) win 4380 <mss
1460,nop,wscale 0,nop,nop,timestamp 2392363491 0,sackOK,eol>
22:22:09.625082 IP 172.16.20.100.53875 > 172.16.20.2.80: S 51116678:51116678(0) win 4380 <mss
1460,nop,wscale 0,nop,nop,timestamp 2392364691 0,sackOK,eol>
22:22:10.825194 IP 172.16.20.100.53875 > 172.16.20.2.80: S 51116678:51116678(0) win 4380 <mss
1460,sackOK,eol>
4 packets captured
4 packets received by filter
0 packets dropped by kernel
What should the LTM Specialist do to solve the problem?
A. Enable the virtual server.
B. Edit the packet filter rules.
C. Configure the virtual server to use SNAT.
D. Modify the monitor of the pool.
Answer: C

NEW QUESTION: 3
デフォルトのCisco Discovery Protocol設定に関する正しい記述はどれですか。
A. CDPv2広告がブロードキャストされています。
B. FastEthernetインターフェイスでCDPv1が無効になっています。
C. CDPv2アドバタイズメントはユニキャストです。
D. CDPv1はフレームリレーサブインターフェイスで有効になります。
Answer: A


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