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Exam Code: AICP Dumps

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NEW QUESTION: 1
Which two statements regarding OSPFv2 or OSPFv3 authentication are correct? (Choose two.)
A. OSPFv2 relies on the native security stack that uses IPsec.
B. OSPFv3 supports MD5 or SHA authentication.
C. OSPFv3 relies on the native security stack that uses IPsec.
D. OSPFv2 supports MD5 authentication.
E. OSPFv2 supports MD5 or SHA authentication.
F. OSPFv3 supports MD5 authentication.
Answer: C,D
Explanation:
Explanation

NEW QUESTION: 2
A developer is writing an application with three java Persistence API entities: order, customer, and Address. There is a many-to-one relationship between order and customer, and a one to-many relationship between customer and Address.
Which two Criteria queries will return the orders of all customers who have an address whose value specified by the String parameter postalcode? (Choose two)
A. String postalCode = . . .
Criteria Builder cb = . . .
CriteriaQuery<order> cq = cb.createQuery (Order.class);
Root <order> order = cq.from(order.class);
Join <order, Customer> customer = order.join(Order_.customer);
Root <Order> order = cq.from (Order.class);
Join <customer, Address> address = customer join (Order_.customer)
cq.where (cb.equal (address.get(Address_.postalCode), postalCode));
cq.select (order). Distinct (true);
// query execution code here
.. .
B. String postalCode = . . .
Criteria Builder cb = . . .
Root <Order> order = cq.from (Order.class);
order.join (order_. customer).join(Customer_.addresses);
cq.where (cb.equal (address.get(Address_.postalCode), postalCode));
cq.select (order). Distinct (true);
// query execution code here
C. String postalCode = ...
CriteriaBuilder cb = ...
Root<order> order = cq.from (Order . class) ,
Join<order, Address> address = order.join(Customer_.addresses);
cq.where(ct>.equal(address.get(Address_.postalCode), postalCode));
cq-select(order).distinct(true);
// query execution code here
.. .
D. String postalCode = ...
CriteriaBuilder cb = ...
Root<order> order = cq.from (Order . class ) ,
Join<order, Address> address = order . join (Order_. customer).join (Customer_.addresses); cq.where <cb.equal (address.get(Address_.postalCode) , postalCode) ) ; cq.selec:(order).distinct (true);
// query execution code here
.. .
Answer: A,D
Explanation:
Explanation/Reference:
A: Join Order and Customer and join Customer and Address. Works fine.
Not B: Chained joined not set up correctly.
C: Join Order and Address through first joining Order and Customer.
Not D: Cannot Join Order Address it just one single join. Need to chain the join.
Note: Querying Relationships Using Joins
For queries that navigate to related entity classes, the query must define a join to the related entity by calling one of the From.join methods on the query root object or another join object. The join methods are similar to the JOIN keyword in JPQL.
The target of the join uses the Metamodel class of type EntityType<T> to specify the persistent field or property of the joined entity.
The join methods return an object of type Join<X, Y>, where X is the source entity and Y is the target of the join. In the following code snippet, Pet is the source entity, Owner is the target, and Pet_ is a statically generated metamodel class:
CriteriaQuery<Pet> cq = cb.createQuery(Pet.class);
Root<Pet> pet = cq.from(Pet.class);
Join<Pet, Owner> owner = pet.join(Pet_.owners);
Joins can be chained together to navigate to related entities of the target entity without having to create a Join<X, Y> instance for each join:
CriteriaQuery<Pet> cq = cb.createQuery(Pet.class);
Root<Pet> pet = cq.from(Pet.class);
Join<Owner, Address> address = cq.join(Pet_.owners).join(Owner_.addresses); Reference: Using the Criteria API and Metamodel API to Create Basic Typesafe Queries

NEW QUESTION: 3
Which of the following would best describe the difference between white-box testing and black-box testing?
A. Black-box testing involves the business units
B. Black-box testing uses the bottom-up approach.
C. White-box testing is performed by an independent programmer team.
D. White-box testing examines the program internal logical structure.
Answer: D
Explanation:
Black-box testing observes the system external behavior, while white-box testing is a detailed exam of a logical path, checking the possible conditions.
Source: Information Systems Audit and Control Association, Certified Information Systems
Auditor 2002 review manual, chapter 6: Business Application System Development,
Acquisition, Implementation and Maintenance (page 299).

NEW QUESTION: 4
Project1とProject2という名前の2つのサイトコレクションを作成する予定です。サイトコレクションは、パートナー企業の外部ユーザーとのコラボレーションに使用されます。すべての外部ユーザーは、独自のMicrosoft Azure Active Directory(Azure AD)テナントを持つパートナー企業に属します。
Project1およびProject2には次の要件があります。
*内部ユーザーはProject1のコンテンツをパートナーのみからの外部ユーザーと共有できる必要があります
* Contoso、Ltd.という名前の会社
*内部ユーザーは、Project2のコンテンツをパートナー企業のユーザーと共有できる必要があります。各サイトコレクションの共有設定とドメインベースのフィルター設定を構成する必要があります。
あなたは何をするべきか?回答するには、回答エリアで適切なオプションを選択します。
注:それぞれの正しい選択には1ポイントの価値があります。

Answer:
Explanation:

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