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Vendor: SAP

Exam Code: C-HCMP-2311 Dumps

Questions and Answers: 104

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NEW QUESTION: 1
A network administrator reviews the following command output while troubleshooting a system that is unable to connect to the www.comptia.com website:

Which of the following is the reason the system cannot connect?
A. A cable is not connected to the NIC.
B. The interface eth0 Is using an APIPA address.
C. The DNS server is under maintenance.
D. The domain complia.com is having network issues.
Answer: D

NEW QUESTION: 2
You want to add a custom attribute to an out-of-the-box (OOT8) struct called CaseDetails. You create a custom struct called CustomCaseDetails. Both structs are shown in the diagram:

Which association should you model next?
A. CaseDetails aggregates CustomCaseDetails.
B. CaseDetails is assigned to CustomCaseDetails
C. CustomCase Details aggregates CaseDetails.
D. CustomCaseDetails subclasses CaseDetails.
Answer: D

NEW QUESTION: 3
Sie unterstützen eine im Exponat gezeigte Datenbankstruktur. (Klicken Sie auf die Schaltfläche "Ausstellen".)

Sie müssen eine Abfrage schreiben, die die folgenden Details anzeigt:
* Gesamtumsatz nach Verkäufern, Jahr, Stadt und Land
* Zwischensummen nur auf Stadt- und Länderebene
* Eine Gesamtsumme des Umsatzes
Welche Transact-SQL-Abfrage sollten Sie verwenden?
A. SELECT SalesPerson.Name, Land, Stadt,
DatePart (yyyy, SaleDate) AS Jahr, Summe (Betrag) AS Total
FROM Sale INNER JOIN SalesPerson
ON Sale.SalesPersonID = SalesPerson.SalesPersonID
GROUP BY ROLLUP (SalesPerson.Name, DatePart (JJJJ, Verkaufsdatum), Stadt, Land)
B. SELECT SalesPerson.Name, Land, Stadt,
DatePart (yyyy, SaleDate) AS Jahr, Summe (Betrag) AS Total
FROM Sale INNER JOIN SalesPerson
ON Sale.SalesPersonID = SalesPerson.SalesPersonID
GROUP BY CUBE (SalesPerson.Name, DatePart (JJJJ, Verkaufsdatum), Stadt, Land)
C. SELECT SalesPerson.Name, Land, Stadt,
DatePart (yyyy, SaleDate) AS Jahr, Summe (Betrag) AS Total
FROM Sale INNER JOIN SalesPerson
ON Sale.SalesPersonID = SalesPerson.SalesPersonID
Gruppieren nach Gruppierungssätzen ((SalesPerson.Name, Country, City, DatePart (yyyy, SaleDate)), (Country, City), (Country), ())
D. SELECT SalesPerson.Name, Land, Stadt,
DatePart (yyyy, SaleDate) AS Jahr, Summe (Betrag) AS Total
FROM Sale INNER JOIN SalesPerson
ON Sale.SalesPersonID = SalesPerson.SalesPersonID
GROUP BY CUBE (SalesPerson.Name, Land, Stadt, Datum (JJJJ, Verkaufsdatum))
Answer: C
Explanation:
Be careful with this question, because on exam can be different options for answer.
And none of them is correct: D You should report this question.

NEW QUESTION: 4
With the automatic clearing program, a user can clear open items for which of the following items? There are
2 correct answers to this question.
A. General ledger
B. Special general ledger indicator
C. Currency
D. Subledger accounts
Answer: A,D


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