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Vendor: IBM

Exam Code: C1000-199 Dumps

Questions and Answers: 104

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NEW QUESTION: 1
Ihr Netzwerk enthält eine Active Directory-Domäne mit dem Namen contoso.com, die mit einem Azure Active Directory-Mandanten mit dem Namen contoso.onmicrosoft.com synchronisiert wird. Der Mandant enthält nur Standarddomänennamen.
Die Domäne enthält die in der folgenden Tabelle aufgeführten Benutzer.

Die Benutzer haben Wertesätze für ihr Benutzerkonto, wie in der folgenden Tabelle gezeigt.

Sie möchten Azure Multi-Factor Authentication (MFA) mithilfe der folgenden Massenaktualisierungsdatei mit dem Namen File1 aktivieren.
Benutzername, MFA-Status
CN = User1, DC = Contoso, DC = onmicrosoft, DC = com, Aktiviert
[email protected], Aktiviert
[email protected], Aktiviert
Wählen Sie für jede der folgenden Anweisungen Ja aus, wenn die Anweisung wahr ist. Andernfalls wählen Sie Nein.
HINWEIS: Jede richtige Auswahl ist einen Punkt wert.

Answer:
Explanation:

Explanation


NEW QUESTION: 2
Note: This question is part of a series of questions that use the same or similar answer choices. An answer choice may be correct for more than one question in the series. Each question is independent of the other questions in this series. Information and details provided in a question apply to that question.
You have a database for a banking system. The database has two tables named tblDepositAcct and tblLoanAcct that store deposit and loan accounts, respectively/ Both tables contain the following columns:

You need to run a query to find the total number of customers who have both deposit and loan accounts.
Which Transact-SQL statement should you run?
A. SELECT COUNT (DISTINCT COALESCE(D.CustNo, L.CustNo))FROM tblDepositAcct
DFULL JOIN tblLoanAcct L ON D.CustNo = L.CustNoWHERE D.CustNo IS NULL OR
B. CustNo
C. CustNo IS NULL
D. SELECT COUNT (DISTINCT CustNo)FROM tblDepositAcct D, tblLoanAcct LWHERE
E. CustNo = L.CustNo
F. SELECT COUNT(*)FROM (SELECT CustNoFROM tblDepositAcctEXCEPTSELECT
CustNoFROM tblLoanAcct) R
G. SELECT COUNT(*)FROM (SELECT CustNoFROM tblDepositAcctUNION ALLSELECT
CustNoFROM tblLoanAcct) R
H. SELECT COUNT(*)FROM tblDepositAcct DFULL JOIN tblLoanAcct L ON D.CustNo =
I. SELECT COUNT(*)FROM (SELECT CustNoFROM tblDepositAcctUNIONSELECT
CustNoFROM tblLoanAcct) R
J. SELECT COUNT(*)FROM (SELECT AcctNoFROM tblDepositAcctINTERSECTSELECT
AcctNoFROM tblLoanAcct) R
K. SELECT COUNT(DISTINCT L.CustNo)FROM tblDepositAcct DRIGHT JOIN
tblLoanAcct L ON D.CustNo = L.CustNoWHERE D.CustNo IS NULL
Answer: J
Explanation:
The SQL INTERSECT operator is used to return the results of 2 or more SELECT statements. However, it only returns the rows selected by all queries or data sets. If a record exists in one query and not in the other, it will be omitted from the INTERSECT results.
References: https://www.techonthenet.com/sql/intersect.php

NEW QUESTION: 3

A. 0
B. 1
C. 2
D. 3
E. 4
Answer: D


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