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NEW QUESTION: 1
Consider these two alternative methods to call a connector from a custom API:
* Method A: req.oracleMobile.connectors.get("AlbumsConn",
"albums",{versionToInvoke: "1.0"}).then( ..etc.. );
* Method B: req.oracleMobile.connectors.AlbumsConn.get("albums").then( ..etc.. ); The connector has been created and version 1 is available to call. You decide to use method rather than method A in your custom API code to call the connector.
Which step do you need to perform to ensure that your code runs as desired at run time?
A. There is nothing to do because the calls are identical and both will work.
B. In method B's then() function, you must define the connector version to use.
C. In the MCS UI, you must select the connector and version for the uploaded custom API.
D. You must define the connector dependency in the package.json file.
Answer: D
NEW QUESTION: 2
What is the transmogrify anti-forensics technique?
A. changing the file header of a malicious file to another file type
B. concealing malicious files in ordinary or unsuspecting places
C. hiding a section of a malicious file in unused areas of a file
D. sending malicious files over a public network by encapsulation
Answer: A
Explanation:
Reference:
https://www.csoonline.com/article/2122329/the-rise-of-anti-forensics.html#:~:text=Transmogrify%20is% 20similarly%20wise%20to,a%20file%20from%2C%20say%2C%20.
NEW QUESTION: 3
Sie verwalten eine Microsoft SQL Server 2012-Datenbank mit dem Namen ContosoDb. Die Tabellen sind wie im Exponat angegeben definiert. (Klicken Sie auf die Schaltfläche "Ausstellen".)
Sie müssen Zeilen aus der Orders-Tabelle für die Customers-Zeile mit dem CustomerId-Wert 1 im folgenden XML-Format anzeigen.
Welche Transact-SQL-Abfrage sollten Sie verwenden?
A. SELECT OrderId, OrderDate, Amount, Name, Country FROM Orders
INNER JOIN Customers ON Orders.CustomerId = Customers.CustomerId
WHERE Customers.CustomerId = 1
FÜR XML AUTO
B. SELECT Name AS '@Name', Land AS '@Country', OrderId, OrderDate, Betrag FROM Orders INNER JOIN Customers ON Orders.CustomerId = Customers.CustomerId WHERE Customers.CustomerId = 1 FOR XML PATH ('Customers' )
C. SELECT OrderId, OrderDate, Amount, Name, Country FROM Orders
INNER JOIN Customers ON Orders.CustomerId = Customers.CustomerId
WHERE Customers.CustomerId = 1
FÜR XML AUTO ELEMENTE
D. SELECT OrderId, OrderDate, Amount, Name, Country FROM Orders
INNER JOIN Customers ON Orders.CustomerId = Customers.CustomerId
WHERE Customers.CustomerId = 1
FÜR XML RAW ELEMENTE
E. WÄHLEN Sie Name, Land, Bestell-ID, Bestelldatum, Betrag von Bestellungen
INNER JOIN Customers ON Orders.CustomerId = Customers.CustomerId
WHERE Customers.CustomerId = 1
FÜR XML AUTO
F. SELECT OrderId, OrderDate, Amount, Name, Country FROM Orders
INNER JOIN Customers ON Orders.CustomerId = Customers.CustomerId
WHERE Customers.CustomerId = 1
FÜR XML RAW
G. SELECT Name, Land, OrderId, OrderDate, Betrag FROM Orders
INNER JOIN Customers ON Orders.CustomerId = Customers.CustomerId
WHERE Customers.CustomerId = 1
FÜR XML AUTO ELEMENTE
H. WÄHLEN Sie den Namen ALS "Kunden / Name", das Land ALS "Kunden / Land", die Bestellnummer, das Bestelldatum und den Auftragsbetrag INNER JOIN Customers ON Orders.CustomerId = Customers.CustomerId WHERE Customers.CustomerId = 1 FOR XML PATH (' Kunden')
Answer: C
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