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Exam Code: EMEA-Advanced-Support Dumps

Questions and Answers: 104

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NEW QUESTION: 1
Which two clock rates does Performance Monitor use to calculate RTP jitter values? (Choose two.)
A. H.263 , 64,000 Hz
B. PCMU (G.711 mu-law) , 8000 Hz
C. H.263 , 90,000 Hz
D. PCMA (G.711 A-law) , 16000 Hz
E. PCMU (G.711 mu-law) , 32000 Hz
Answer: B,C
Explanation:
Explanation/Reference:
References:

NEW QUESTION: 2
Hinweis: Diese Frage ist Teil einer Reihe von Fragen, bei denen die gleichen oder ähnliche Antwortmöglichkeiten verwendet werden. Eine Antwortauswahl kann für mehr als eine Frage in der Reihe richtig sein. Jede Frage ist unabhängig von den anderen Fragen in dieser Reihe. In einer Frage angegebene Informationen und Details gelten für diese Frage.
Sie haben eine Datenbank für ein Bankensystem. Die Datenbank enthält zwei Tabellen mit den Namen tblDepositAcct und tblLoanAcct, in denen Einlagen- und Darlehenskonten gespeichert sind. Beide Tabellen enthalten die folgenden Spalten:

Sie müssen eine Abfrage ausführen, um die Gesamtzahl der Kunden zu ermitteln, die sowohl Einzahlungs- als auch Darlehenskonten haben.
Welche Transact-SQL-Anweisung sollten Sie ausführen?
A. SELECT COUNT (DISTINCT L.CustNo) VON tblDepositAcct DRIGHT JOIN tblLoanAcct L ON D.CustNo = L.CustNoWHERE D.CustNo IS NULL
B. SELECT COUNT (*) FROM (SELECT CustNoFROM tblDepositAcctUNION ALLSELECT CustNoFROM tblLoanAcct) R
C. SELECT COUNT (DISTINCT COALESCE (D.CustNo, L.CustNo)) FROM tblDepositAcct DFULL JOIN tblLoanAcct L ON D.CustNo = L.CustNoWhere
D. SELECT COUNT (*) FROM (SELECT CustNoFROM tblDepositAcctEXCEPTSELECT CustNoFROM tblLoanAcct) R
E. SELECT COUNT (*) FROM tblDepositAcct DFULL JOIN tblLoanAcct L ON D.CustNo = L.CustNo
F. SELECT COUNT (*) FROM (SELECT AcctNoFROM tblDepositAcctINTERSECTSELECT AcctNoFROM tblLoanAcct) R
G. SELECT COUNT (*) FROM (SELECT CustNoFROM tblDepositAcctUNIONSELECT CustNoFROM tblLoanAcct) R
H. SELECT COUNT (DISTINCT D.CustNo) FROM tblDepositAcct D, tblLoanAcct LWHERE D.CustNo = L.CustNo
Answer: F
Explanation:
Erläuterung
Der SQL INTERSECT-Operator wird verwendet, um die Ergebnisse von 2 oder mehr SELECT-Anweisungen zurückzugeben. Es werden jedoch nur die Zeilen zurückgegeben, die von allen Abfragen oder Datensätzen ausgewählt wurden. Wenn ein Datensatz in einer Abfrage und nicht in der anderen vorhanden ist, wird er in den INTERSECT-Ergebnissen nicht berücksichtigt.
Referenzen: https://www.techonthenet.com/sql/intersect.php

NEW QUESTION: 3
Sie haben drei Geräte in Microsoft Intune registriert, wie in der folgenden Tabelle gezeigt.

Die Gerätekonformitätsrichtlinien in Intune werden wie in der folgenden Tabelle gezeigt konfiguriert.

Wählen Sie für jede der folgenden Anweisungen Ja aus, wenn die Anweisung wahr ist. Andernfalls wählen Sie Nein.
HINWEIS: Jede richtige Auswahl ist einen Punkt wert.

Answer:
Explanation:

Explanation

Device 1:
No because Device1 is in group3 which has Policy1 assigned which requires BitLocker.
Device 2:
No because Device2 is in group3 which has Policy1 assigned which requires BitLocker. Device2 is also in Group2 which has Policy2 assigned but the BitLocker requirement is not configured in Policy2.
Device3:
Yes because Device3 is in Group2 which has Policy2 assigned but the BitLocker requirement is not configured in Policy2.
Reference:
https://blogs.technet.microsoft.com/cbernier/2017/07/11/windows-10-intune-windows-bitlocker-management-ye


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