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Vendor: Fortinet

Exam Code: FCP_FSM_AN-7.2 Dumps

Questions and Answers: 104

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NEW QUESTION: 1
ABAPベースのSAPシステムの一部として機能するICMプロセスのデフォルトのHTTPSポートは何ですか?
正しい答えを選んでください。
応答:
A. 5 $$ 01
B. 443 $$
C. 81 $$
D. 5 $$ 14
Answer: B

NEW QUESTION: 2
Your business user has created a purchase order (PO) that has the following attributes:
Accrue at Receipt = Yes
Matching Option = 2 way
Receipt Close Tolerance = 100%
After approval, the PO is closed for receiving without creating a receipt. An AP invoice is created by matching to the PO. The user now runs Create Accounting for Receiving Transactions and then the "Import and Process Cost transactions" ESS (Enterprise Scheduler Service) job using the Transaction Source parameter as "Oracle Payables". The user notices that there is no cost transferred to the projects. Identify two reasons for this problem. (Choose two.)
A. When you have an AP invoice that is matched against a PO with Accrue at Receipt set to NO, cost is transferred to projects by receipt accounting.
B. When you have an AP invoice that is matched against a PO with Accrue at Receipt set to YES, cost is transferred to projects by Cost Management and not by Payables.
C. When you have an AP invoice that is matched against a PO with Accrue at Receipt set to Yes, cost is transferred to projects only if there are accounted receipt lines.
D. When you have an AP invoice that is matched against a PO with Accrue at Receipt set to Yes, cost is transferred to project by payables.
Answer: A,C

NEW QUESTION: 3



A. 192.168.25.28 255.255.255.252
B. 192.168.25.0 255.255.255.240
C. 192.168.25.28 255.255.255.240
D. 192.168.25.0 255.255.255.252
E. 192.168.25.16 255.255.255.240
F. 192.168.25.16 255.255.255.252
Answer: E
Explanation:
The binary version of 20 is 10100.
The binary version of 16 is 10000.
The binary version of 24 is 11000.
The binary version of 28 is 11100.
The subnet mask is /28. The mask is 255.255.255.240.
Note:
From the output above, EIGRP learned 4 routes and we need to find out the summary of them:
+
192.168.25.16
+
192.168.25.20
+
192.168.25.24
+
192.168.25.28 -> The increment should bE. 28 - 16 = 12 but 12 is not an exponentiation of 2 so we must choose 16 (24). Therefore the subnet mask is /28 (=1111 1111.1111 1111.1111 1111.11110000) =
255.255.255.240
So the best answer should be 192.168.25.16 255.255.255.240

NEW QUESTION: 4
CORRECT TEXT
A ___________ is a program that can be useful in preventing cookies and Java applets from accessing a system.
Answer:
Explanation:
Firewall


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