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NEW QUESTION: 1
CORRECT TEXT
Answer:
Explanation:
Router>enable Router#config terminal Router(config)#hostname Apopka 2) Enable-secret password (cisco10): Apopka(config)#enable secret cisco10 3) Set the console password to RouterPass: Apopka(config)#line console 0 Apopka(config-line)#password RouterPass Apopka(config-line)#login Apopka(config-line)#exit 4) Set the Telnet password to scan90: Apopka(config)#line vty 0 4 Apopka(config-line)#password scan90 Apopka(config-line)#login Apopka(config-line)#exit 5) Configure Ethernet interface (on the right) of router Apopka: The subnet mask of the Ethernet network 209.165.201.0 is 27. From this subnet mask, we can find out the increment by converting it into binary form, that is /27 = 1111 1111.1111 1111.1111 1111.1110 0000. Pay more attention to the last bit 1 because it tells us the increment, using the formula: Increment = 2place of the last bit 1 (starts counting from 0,from right to left), in this case increment = 25 = 32. Therefore: Increment: 32 Network address: 209.165.201.0 Broadcast address: 209.165.201.31 (because 209.165.201.32 is the second subnetwork, so the previous IP - 209.165.201.31 - is the broadcast address of the first subnet). -> The second assignable host address of this subnetwork is 209.165.201.2/27 Assign the second assignable host address to Fa0/0 interface of Apopka router: Apopka(config)#interface Fa0/0 Apopka(config-if)#ip address 209.165.201.2 255.255.255.224 Apopka(config-if)#no shutdown Apopka(config-if)#exit 6) Configure Serial interface (on the left) of router Apopka: Using the same method to find out the increment of the Serial network: Serial network 192.0.2.128/28: Increment: 16 (/28 = 1111 1111.1111 1111.1111 1111.1111 0000) Network address: 192.0.2.128 (because 8 * 16 = 128 so 192.0.2.128 is also the network address of this subnet) Broadcast address: 192.0.2.143 -> The last assignable host address in this subnet is 192.0.2.142/28. Assign the last assignable host address to S0/0/0 interface of Apopka router: Apopka(config)#interface S0/0/0 (or use interface S0/0 if not successful) Apopka(config-if)#ip address 192.0.2.142 255.255.255.240 Apopka(config-if)#no shutdown Apopka(config-if)#exit 7) Configure RIP v2 routing protocol: Apopka(config)#router rip Apopka(config-router)#version 2 Apopka(config-router)#network 209.165.201.0 Apopka(config-router)#network 192.0.2.128
Apopka(config-router)#end
Save the configuration:
Apopka#copy running-config startup-config
Finally, you should use the ping command to verify all are working properly!

NEW QUESTION: 2

A. Option B
B. Option D
C. Option A
D. Option C
Answer: B

NEW QUESTION: 3
ネットワークエンジニアは、提供されている図に従って、矛盾するCisco Discovery Protocolネイバーに気付きます。エンジニアは、Cisco Discovery Protocolを使用する単一のネイバーのみに気づきますが、ルーティングネイバー関係がいくつかあります。出力に単一のネイバーのみが表示される原因は何ですか？
A. ルーターはレイヤー2スイッチを介して接続されています。
B. IPルーティングは隣接デバイスで無効になっています。
C. シスコエクスプレスフォワーディングはローカルで有効になっています。
D. Cisco Discovery Protocolアドバタイズメントは、ローカルデバイスとリモートデバイスの間で一貫性がありません。
Answer: A
Explanation:
If all of the routers are connected to each other using a layer 2 switch, then each router will only have the single switch port that it connects to as its neighbor. Even though multiple routing neighbors can be formed over a layer 2 network, only the physical port that it connects to will be seen as a CDP neighbor. CDP can be used to determine the physical topology, but not necessarily the logical topology.

NEW QUESTION: 4
Extreme Programming (XP) defines four basic activities that are performed during the software development process. These include designing, coding, testing and ...?
A. Communicating
B. Listening
C. Leveling
D. Collaborating
Answer: B

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Exam Code: FCP_ZCS-AD-7.4 Dumps

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