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NEW QUESTION: 1
-- Exhibit- -- Exhibit -
The first two paragraphs (lines 1-27) establish a contrast between which two parts of the narrator's life?
A. friends and enemies
B. girls and boys
C. mother and father
D. home and school
E. teachers and students
Answer: D
NEW QUESTION: 2
Which element is included in an incident response plan?
A. day-to-day firefighting
B. siloed approach to communications
C. junior analyst approval
D. organization mission
Answer: D
Explanation:
Explanation/Reference:
Explanation:
NEW QUESTION: 3
Azure Cosmos DB SQL APIを使用してAzure Cosmos DBソリューションを開発しています。データには数百万のドキュメントが含まれています。各ドキュメントには数百のプロパティが含まれる場合があります。
ドキュメントのプロパティには、パーティション化のための個別の値は含まれていません。 Azure Cosmos DBは、時間の経過とともにすべてのパーティションにワークロードを均等に分散させることにより、アプリケーションのパフォーマンスニーズを満たすために、データベース内の個々のコンテナーをスケーリングする必要があります。
パーティションキーを選択する必要があります。
どの2つのパーティションキーを使用できますか？それぞれの正解は完全なソリューションを示します。
注：それぞれの正しい選択は1ポイントの価値があります。
A. ドキュメントに頻繁に表示されない単一のプロパティ値
B. コレクション名を含む値
C. ランダムなサフィックスが追加された複数のプロパティ値の連結
D. ドキュメントに頻繁に出現する単一のプロパティ値
E. プロパティ値に付加されたハッシュサフィックス
Answer: C,E
Explanation:
You can form a partition key by concatenating multiple property values into a single artificial partitionKey property. These keys are referred to as synthetic keys.
Another possible strategy to distribute the workload more evenly is to append a random number at the end of the partition key value. When you distribute items in this way, you can perform parallel write operations across partitions.
Note: It's the best practice to have a partition key with many distinct values, such as hundreds or thousands. The goal is to distribute your data and workload evenly across the items associated with these partition key values. If such a property doesn't exist in your data, you can construct a synthetic partition key.
References:
https://docs.microsoft.com/en-us/azure/cosmos-db/synthetic-partition-keys
NEW QUESTION: 4
For the deployment of new features in monolith architecture, why does it take longer time than microservices architecture?
A. Because need to load all used & unused modules of applications
B. Because need to load only all used modules of applications
C. Because need to load all unused modules of applications
D. Because need waiting approval from Project Manager
Answer: A
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