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Vendor: Fortinet

Exam Code: FCSS_EFW_AD-7.6 Dumps

Questions and Answers: 104

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NEW QUESTION: 1
Welches Datenobjekt kann mit den Planungsergebnissen eines Routings aktualisiert werden?
Bitte wählen Sie die richtige Antwort.
A. Produktionsversion
B. Materialstamm
C. Produktionsplanungsprofil
D. Dispositionsprofil
Answer: B

NEW QUESTION: 2
You are the security analyst working for a private company out of France. Your current assignment is to obtain credit card information from a Swiss bank owned by that company. After initial reconnaissance, you discover that the bank security defenses are very strong and would take too long to penetrate. You decide to get the information by monitoring the traffic between the bank and one of its subsidiaries in London. After monitoring some of the traffic, you see a lot of FTP packets traveling back and forth. You want to sniff the traffic and extract usernames and passwords. What tool could you use to get this information?
A. Snort
B. RaidSniff
C. Ettercap
D. Airsnort
Answer: C
Explanation:
Ettercap is the best answer as that tool makes extracting of username and password easier.

NEW QUESTION: 3
CORRECT TEXT
2.a.3-R6-D. In an Isilon cluster, what is the correct sequence of operations for a client write when Forward Error Correction (FEC) is used for data protection ?
Answer:
Explanation:
B,
A, D, C

NEW QUESTION: 4
The Wireless Transport Layer Security Protocol (WTLS) in the Wireless
Application Protocol (WAP) stack provides for security:
A. Between the WAP client and the gateway
B. Between the WAP content server and the WAP client
C. Between the Internet and the content server
D. Between the WAP gateway and the content server
Answer: A
Explanation:
Transport Layer Security (TLS) provides for security between the
content server on the Internet and the WAP gateway. (Answer "Between the WAP gateway and the content server" is, thus, incorrect.) Similarly, WTLS provides security between the WAP
mobile device (client software) and the WAP gateway. Since WAP
cannot interface directly with the Internet, all WAP information has
to be converted to HTTP in the WAP gateway to enable it to exchange
information with the Internet content servers. The simple block diagram illustrates these concepts.
Exhibit:

image024
A vulnerability occurs since data encrypted with wireless protocols
has to be decrypted in the WAP gateway and then re-encrypted
with the Internet protocols. This process is reversed when data flows
from the Internet content servers to the WAP client. Thus, the information is vulnerable while it is in the decrypted state on the WAP gateway. This condition is known as the WAP Gap. In order to
address this issue, the WAP Forum has put forth specifications that
will reduce this vulnerability and, thus, support e-commerce applications.
These specifications are defined in WAP 1.2 as WMLScript
Crypto Library and the WAP Identity Module (WIM). The
WMLScript Crypto Library supports end-to-end security by providing
for cryptographic functions to be initiated on the WAP client from
the Internet content server. These functions include digital signatures originating with the WAP client and encryption and decryption of data. The WIM is a tamper-resistant device, such as a smart card, that
cooperates with WTLS and provides cryptographic operations during
the handshake phase.
The WAP Forum is also considering another alternative to providing
the end-to-end encryption for WAP. This alternative, described in
WAP specification 1.3, is the use of a client proxy server that communicates authentication and authorization information to the wireless network server.
*Answer "Between the Internet and the content server" is incorrect since the content server is on the Internet side of the communication and answer "Between the WAP content server and the WAP client" assumes a direct interface between the content server and the client without going through the necessary Internet and wireless protocols.


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