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Exam Code: FlashArray-Implementation-Specialist Dumps

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NEW QUESTION: 1
Which of the following ciphers is a subset on which the Vigenere polyalphabetic cipher was based on?
A. SIGABA
B. Enigma
C. Caesar
D. The Jefferson disks
Answer: C
Explanation:
Explanation/Reference:
Explanation:
Julius Caesar (100-44 B.C.) developed a simple method of shifting letters of the alphabet. He simply shifted the alphabet by three positions.
Today, this technique seems too simplistic to be effective, but in the time of Julius Caesar, not very many people could read in the first place, so it provided a high level of protection. The Caesar cipher is an example of a monoalphabetic cipher. Once more people could read and reverse-engineer this type of encryption process, the cryptographers of that day increased the complexity by creating polyalphabetic ciphers.
In the 16th century in France, Blaise de Vigenere developed a polyalphabetic substitution cipher for Henry III. This was based on the Caesar cipher, but it increased the difficulty of the encryption and decryption process Incorrect Answers:
B: The Vigenere polyalphabetic cipher is based on the Caesar cipher, not the Jefferson disks.
C: The Vigenere polyalphabetic cipher is based on the Caesar cipher, not Enigma.
D: The Vigenere polyalphabetic cipher is based on the Caesar cipher, not SIGABA.
References:
Harris, Shon, All In One CISSP Exam Guide, 6th Edition, McGraw-Hill, 2013, pp. 761-762

NEW QUESTION: 2
As you review this Security Policy, what changes could you make to accommodate Rule 4?

A. Modify the columns Source or Destination in Rule 4
B. Remove the service HTTP from the column Service in Rule 4.
C. Nothing at all
D. Modify the column VPN in Rule 2 to limit access to specific traffic.
Answer: D

NEW QUESTION: 3
You are developing a solution to insert and update records in a table named Table l. Table l is structured as shown in the following table.

You have the following X++ code:

You need to identify the output of the X++ code.
What should you identify?
A. Data error
B. Error
C. Break
D. Max value
Answer: D


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