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NEW QUESTION: 1
展示を参照してください。 PC-1はポート8080でWebサーバーにアクセスする必要があります。このトラフィックを許可するには、SW2ポートG0 / 0でインバウンド方向に適用されるアクセス制御リストにどのステートメントを追加する必要がありますか。
A. 許可ホスト192.168.0.5 it8080ホスト172.16.0.2
B. 許可ホスト192.168.0.5ホスト172.16.0.2 eq 8080
C. ホスト172.16.0.2ホスト192.168.0.5 eq8080を許可します
D. 許可ホスト192.168.0.5 eq8080ホスト172.16.0.2
Answer: D
Explanation:
Explanation
The inbound direction of G0/0 of SW2 only filter traffic from Web Server to PC-1 so the source IP address and port is of the Web Server.
NEW QUESTION: 2
Why would an IBM SmartCloud Control Desk V7.5 user have two Start Centers?
A. Two Start Centers are assigned to the security group that the user belongs to.
B. The user belongs to two person groups.
C. The user belongs to two security groups.
D. Two Start Centers are assigned to the person group that the user belongs to.
Answer: C
NEW QUESTION: 3
During project execution, a large number of changes are made to the project. The project manager should:
A. wait until all changes are known and print out a new schedule.
B. make approved changes as needed, but retain the schedule baseline.
C. talk to management before any changes are made.
D. make only the changes approved by management.
Answer: B
NEW QUESTION: 4
Answer:
Explanation:
Explanation
An IPv4 address consists of 32 bits. The first x number of bits in the address is the network address and the remaining bits are used for the host addresses. The subnet mask defines howmany bits form the network address and from that, we can calculate how many bits are used for the host addresses.
The formula to calculate the number of hosts in a subnet is 2n - 2. The "n" in the host's formula represents the number of bits used for host addressing.If we apply the formula (22 - 2), we can determine that the following subnets should be configured:
Sales network - /26 - This will provide up to 62 usable IP addresses (64-2 for subnet and broadcast IP) HR network - /27 - This will provide for up to 30usable IP's (32-2) IT - /28 - This will provide for up to 14 usable IP's (16-2) Finance - /26 - Note that a /27 is 32 IP addresses but 2 of those are reserved for the network and broadcast IP's and can't be used for hosts.
Marketing - /28
If we add up howmany IP blocks are used that is 64+32+16+64+16=192.
A /24 contains 256 IP addresses, so 256-192=64.
So the last unused box should be a /26, which equates to 64 addresses
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