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NEW QUESTION: 1
Which term describes an ordered list of partitions that an IP phone can search before completing a call?
A. calling search space
B. called search space
C. route list
D. route group
Answer: A
NEW QUESTION: 2
Which application environment of following is NFV often deployed? (Multiple Choice)
A. Network node
B. Data center
C. Client/Server
D. User access side
Answer: A,B,D
NEW QUESTION: 3
A company is implementing a publish-subscribe (Pub/Sub) messaging component by using Azure Service Bus. You are developing the first subscription application.
In the Azure portal you see that messages are being sent to the subscription for each topic. You create and initialize a subscription client object by supplying the correct details, but the subscription application is still not consuming the messages.
You need to complete the source code of the subscription client
What should you do?
A. subscriptionClient = new SubscriptionClient(ServiceBusConnectionString, TopicName, SubscriptionName);
B. subscriptionClient.RegisterMessageHandler(ProcessMessagesAsync, messageHandlerOptions);
C. await subscriptionClient.AddRuleAsync(new RuleDescription (RuleDescription.DefaultRuleName, new TrueFilter()));
D. await subscriptionClient.CloseAsync();
Answer: B
Explanation:
Using topic client, call RegisterMessageHandler which is used to receive messages continuously from the entity. It registers a message handler and begins a new thread to receive messages.
This handler is waited on every time a new message is received by the receiver.
subscriptionClient.RegisterMessageHandler(ReceiveMessagesAsync, messageHandlerOptions); References:
https://www.c-sharpcorner.com/article/azure-service-bus-topic-and-subscription-pub-sub/
NEW QUESTION: 4
A. SELECT c.custidFROM Sales.Customers c INNER JOIN Sales.Order oON c.custid = o.custid
B. SELECT custid FROM Sales.CustomersINTERSECTSELECT custid FROM
Sales.Orders
C. SELECT c.custidFROM Sales.Customers c LEFT OUTER JOIN Sales.Order o ON c.custid = o.custidWHERE orderid IS NULL
D. SELECT c.custidFROM Sales.Customers c LEFT OUTER Sales.Order oON c.custid = o.custid
Answer: C
Explanation:
Explanation
Inner joins return rows only when there is at least one row from both tables that matches the join condition.
Inner joins eliminate the rows that do not match with a row from the other table. Outer joins, however, return all rows from at least one of the tables or views mentioned in the FROM clause, as long as those rows meet any WHERE or HAVING search conditions. All rows are retrieved from the left table referenced with a left outer join, and all rows from the right table referenced in a right outer join. All rows from both tables are returned in a full outer join.
References: https://technet.microsoft.com/en-us/library/ms187518(v=sql.105).aspx
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