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NEW QUESTION: 1
Note: This question is part of a series of questions that present the same scenario. Each question in the series contains a unique solution that might meet the stated goals. Some question sets might have more than one correct solution, white others might not have a correct solution.
After you answer a question in this section, you will NOT be able to return to it. As a result, these questions will not appear in the review screen.
You have an Azure environment.
You need to create a new Azure virtual machine from an Android laptop.
Solution: You use the PowerApps portal.
Does this meet the goal?
A. No
B. Yes
Answer: A
Explanation:
Explanation
PowerApps lets you quickly build business applications with little or no code. It is not used to create Azure virtual machines. Therefore, this solution does not meet the goal.
PowerApps Portals allow organizations to create websites which can be shared with users external to their organization either anonymously or through the login provider of their choice like LinkedIn, Microsoft Account, other commercial login providers.
References:
https://powerapps.microsoft.com/en-us/blog/introducing-powerapps-portals-powerful-low-code-websites-for-ext
NEW QUESTION: 2
You are checking a DHCP server configuration for video endpoints. What is the role of option 150 in the
configuration?
A. It is the NTP server IPv4 address.
B. It is the TFTP server IPv6 address.
C. It is the TFTP server IPv4 address.
D. It is not necessary to specify the role of option 150.
Answer: C
Explanation:
Explanation/Reference:
Reference: http://www.cisco.com/c/dam/en/us/td/docs/telepresence/endpoint/codec-c-series/tc7/
administration-guide/administering-endpoints-running-tc72-on-ucm1051.pdf
NEW QUESTION: 3
The ANSI X9.52 standard defines a variant of DES encryption with keys
k1, k2, and k3 as:
C = Ek3 [Dk2 [Ek1 [M]]]
What is this DES variant?
A. DESX
B. Triple DES in theEDE mode
C. Triple DES in the EEE mode
D. Double DES with an encryption and decryption with different keys
Answer: B
Explanation:
This version of triple DES performs an encryption (E) of plaintext message M with key k1, a decryption (D) with key k2 (essentially, another encryption), and a third encryption with key k3. Another implementation of DES EDE is accomplished with keys k1 and k2 being independent, but with keys k1 and k3 being identical. This implementation of triple DES is written as: C = Ek1 [Dk2 [Ek1 [M]]] Answer a is incorrect since, in DESX, input plaintext is bitwise XORed with 64 bits of additional key material before encryption with DES, and the output of DES is also bitwise XORed with another 64 bits of key material. Answer b, DES in the EEE, mode is written as: C = Ek3 [Ek2 [Ek1 [M]]] where three consecutive encryptions are performed on plaintext message, M, with three independent keys, k1, k2, k3. Answer c is incorrect since the question contains three encryptions.
Implementing two DES encryptions does not provide the additional security anticipated over a single DES encryption because of the meet-in-the-middle attack. Consider a DES cipher with a key size of p. A double encryption will result in an effective key size of 2p and yield the final result R.Thus, one would anticipate that one would have to search a key space of 22p in an exhaustive search of the keys. However, it can be shown that a search of the key space on the order of 2p is all that is necessary. This search is the same size as required for a single DES encryption. This situation is illustrated as follows: The sequences shown illustrate the first DES encryption of a plaintext message M with all keys k1 through k2p yielding the intermediate encrypted results C1 through C2p. Ek1 [M] C1 Ek2 [M] C2
Ek2p [M] C2p If we have available ciphertext R where R = Ek2 [Ek1 [M]] for a pair of secret keys k1 and k2, for each key m there is only one key k such that Dm[R] = Ek[M] where D is the decipherment of R back from the second DES encipherment. In other words, there are 2p possible keys that will result in the pair [M,R] and, thus, can be found in a search of order 2p.