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NEW QUESTION: 1
When designing a Star Schema, which option does not apply?
A. Dimensional tables are normalized.
B. Dimensional tables have one attribute primary key as Product_ID for products.
C. The fact has several foreign keys that are primary keys in the dimensional table
D. The facts are quantifiable.
E. Fact table is joined to the related dimensional tables.
Answer: A
Explanation:
In a Star Schema the dimensional tables does not need to be normalized.
A Snowflake Schema is a modified Star Schema that has normalized the dimensional tables.
NEW QUESTION: 2
What is the CIDR from the following screenshot?
A. /16 C./16 C./16
B. /32 B./32 B./32
C. /24A./24A./24
D. /8D./8D./8
Answer: D
NEW QUESTION: 3
展示を表示し、ORDERSテーブルとCUSTOMERSテーブルの構造を調べます。
CUST_LAST_NAME列に値Robertsを持つ顧客は1人だけです。
CUST_LAST_NAMEがRobertsでCREDIT_LIMITが600である顧客のORDERSテーブルに行を追加するには、どのINSERTステートメントを使用する必要がありますか？
A. INSERT INTO注文（order_id、order_date、order_mode、（SELECT customer_idFROM CustomersWHERE cust_last_name = 'Roberts' ANDcredit_limit = 600）、order_total）VALUES（1、'10 -mar-2007 '、' direct '、＆customer_id、1000） ;
B. INSERT INTO注文（order_id、order_date、order_mode、（SELECT customer_idFROM CustomersWHERE cust_last_name = 'Roberts' ANDcredit_limit = 600）、order_total）VALUES（1、'10 -mar-2007 '、' direct '、&& customer_id、1000） ;
C. INSERT INTO ordersVALUES（1、'10 -mar-2007 '、' direct '、（SELECT customer_idFROM CustomersWHERE cust_last_name =' Roberts 'ANDcredit_limit = 600）、1000）;
D. INSERT INTO（SELECT o.order_id、o.order_date、o.order_mode、c.customer_id、o.order_totalFROM orders o、Customers cWHERE o.customer_id = c.customer_idAND c.cust_last_name = 'Roberts' ANDc.credit_limit = 600）VALUES（1、'10 -mar-2007 '、' direct '、（SELECT customer_idFROM CustomersWHERE cust_last_name =' Roberts 'ANDcredit_limit = 600）、1000）;
Answer: C
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