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NEW QUESTION: 1
Which calculation computes the EIRP of an antenna?
A. EIRP = Tx power (dBm) + Antenna Gain (dBi) - Cable Loss (dB)
B. EIRP = Antenna Gain (dBi) - Cable Loss (dB) * Tx power (dBm)
C. EIRP= Cable Loss (dB)+ Antenna Gain (dBi) - Tx power (dBm)
D. EIRP = Tx power (dBm) + Antenna Gain (dBi) / Cable Loss (dB)
E. EIRP = Cable Loss (dB)+ Antenna Gain (dBi) / Tx power (dBm)
F. EIRP = Tx power (dBm) * Antenna Gain (dBi) / Cable Loss (dB)
Answer: A
Explanation:
Explanation/Reference:
Explanation:
EIRP (Effective Isotropic Radiated Power)
EIRP (Effective Isotropic Radiated Power) is the actual amount of signal leaving the antenna and is a value measured in db and is based on 3 values:
Transmit Power (dBm)

Cable Loss (dB)

Antenna Gain (dBi)

The dB measures the power of a signal as a function of its ratio to another standardized value. The abbreviation dB is often combined with other abbreviations in order to represent the values that are compared. Here are two examples:
dBm --The dB value is compared to 1 mW.
dBw --The dB value is compared to 1 W.
You can calculate the power in dBs from this formula:
Power (in dB) = 10 * log10 (Signal/Reference)
This list defines the terms in the formula:
log10 is logarithm base 10.
Signal is the power of the signal (for example, 50 mW). Reference is the reference power (for example, 1 mW).
How to find EIRP
To determine EIRP follow this equation:<Transmit Power> -Cable Loss + Antenna Gain = EIRP
https://supportforums.cisco.com/document/49506/snr-rssi-eirp-and-free-space-path-loss

NEW QUESTION: 2
-- Exhibit -- user@router> show route protocol static inet.0: 12 destinations, 12 routes (12 active, 0 holddown, 0 hidden)
+ = Active Route, - = Last Active, * = Both
192.168.1.0/24 *[Static/5] 00:03:13
>to 10.20.106.10 via fe-0/0/5.1
192.168.1.192/26 *[Static/5] 00:03:13
>to 10.20.14.131 via ge-0/0/0.0
192.168.1.192/27 *[Static/5] 00:03:13
>to 10.18.1.1 via ge-0/0/1.0
192.168.1.4/30 *[Static/5] 00:01:06
>to 10.20.14.130 via ge-0/0/0.0
-- Exhibit --
Using the routing table shown in the exhibit, what will be the next-hop IP address used for a destination IP address of
192.168.1.1? (Assume that the only routes to this destination are static routes.)
A. 10.20.106.10
B. 10.20.14.131
C. 10.18.1.1
D. 10.20.14.130
Answer: A

NEW QUESTION: 3

A. unicast IPv6 addresses
B. unicast IPv4 addresses
C. multicast address FF02::5
D. link-local addresses
Answer: C