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Vendor: Juniper

Exam Code: JN0-650 Dumps

Questions and Answers: 104

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NEW QUESTION: 1
You are developing an ASP.NET Web page.
You add a data-bound GridView control.
The GridView contains a TemplateField that includes a DropDownList.
You set the GridViews ClientIDMode property to Static, and you set the ClientIDRowSuffix property to
ProductID.
You need to be able to reference individual DropDownList controls from client-side script by using the
ProductID.
What should you set the ClientIDMode property of the DropDownList to?
A. Static
B. Predictable
C. AutoID
D. Inherit
Answer: B

NEW QUESTION: 2
The cross-company code depreciation area is required in which of the following intercompany transfers?
A. For transfers where you also change the asset class
B. For transfers with nonmatching depreciation areas
C. For transfers between company codes in different countries
D. For all intercompany asset transfers
Answer: B
Explanation:
The cross-company code depreciation area is used exactly for cases where the sender has areas that need to be mapped to areas with different codification on the receiver side. You might need it for transfers that are between counties, but you also might not, as you might need it for the case of the changing asset class.
In questions such as these, you look for the answer that answers the question in all cases.

NEW QUESTION: 3
A user is experiencing a software application error. The user contacts a technician for support. Which of the following will allow the user to issue an invitation to the technician in this scenario?
A. telnet
B. FTP
C. Remote desktop
D. Remote assistance
Answer: D
Explanation:
Section: Mix Questions

NEW QUESTION: 4
If the total bandwidth is 64 kbps and the RTT is 3 seconds, what is the bandwidth delay product?
A. 16,000 bytes
B. 24,000 bytes
C. 32,000 bytes
D. 62,000 bytes
E. 8,000 bytes
Answer: B
Explanation:
Explanation/Reference:
Explanation:
Bandwidth delay product is defined as capacity of a pipe = bandwidth (bits/ sec) * RTT (s) where capacity is specific to TCP and is a bi-product of how the protocol itself operates.
64 kbps = 64.000bps
1byte=8bit
64.000/8=8.000*3=24.000
Reference:
https://supportforums.cisco.com/t5/wan-routing-and-switching/tcp-performance-bandwidth-delay-product/ td-p/765376


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