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Exam Code: NSE7_ZTA-7.2 Dumps

Questions and Answers: 104

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NEW QUESTION: 1
Hinweis: Diese Frage ist Teil einer Reihe von Fragen, die dasselbe Szenario darstellen. Jede Frage in der Reihe enthält eine eindeutige Lösung, mit der die angegebenen Ziele erreicht werden können. Einige Fragensätze haben möglicherweise mehr als eine richtige Lösung, während andere möglicherweise keine richtige Lösung haben.
Nachdem Sie eine Frage in diesem Abschnitt beantwortet haben, können Sie NICHT mehr darauf zurückkommen. Infolgedessen werden diese Fragen nicht im Überprüfungsbildschirm angezeigt.
Ihr Netzwerk enthält die in der folgenden Tabelle aufgeführten Active Directory-Gesamtstrukturen und -Domänen:

Zwischen ForestA und ForestB besteht eine bidirektionale Gesamtstrukturvertrauensstellung.
Jede Domäne in ForestB enthält Benutzerkonten, mit denen Server verwaltet werden.
Sie müssen sicherstellen, dass die zum Verwalten der Server in ForestB verwendeten Benutzerkonten Mitglieder der Serveroperatoren in ForestA sind.
Lösung: In DomainBRoot fügen Sie die Benutzer der Gruppe "Serveroperatoren" hinzu. Sie ändern die Mitgliedschaft der Server-Operatoren in ForestA.
Erfüllt dies das Ziel?
A. Nein
B. ja
Answer: A
Explanation:
Explanation
References:
https://docs.microsoft.com/en-us/windows/security/identity-protection/access-control/active-directory-security-g

NEW QUESTION: 2
Which technology reduces data loss by identifying sensitive information stored in public computing environments?
A. Cisco Cloudlock
B. Cisco HyperFlex
C. Cisco SDA
D. Cisco Firepower
Answer: A

NEW QUESTION: 3
Given the code fragment:
List<Integer> list1 = Arrays.asList(10, 20);
List<Integer> list2 = Arrays.asList(15, 30);
//line n1
Which code fragment, when inserted at line n1, prints 10 20 15 30?
A. list1.stream()
. flatMap(list2.stream().flatMap(e1 -> e1.stream())
. forEach(s -> System.out.println(s + " "));
B. Stream.of(list1, list2)
. flatMap(list -> list.intStream())
. forEach(s -> System.out.print(s + " "));
C. Stream.of(list1, list2)
. flatMapToInt(list -> list.stream())
. forEach(s -> System.out.print(s + " "));
D. Stream.of(list1, list2)
. flatMap(list -> list.stream())
. forEach(s -> System.out.print(s + " "));
Answer: A

NEW QUESTION: 4
どの3つのステートメントは統合データベース・リプレイについて真ですか。
A. ワークロードの取得とリプレイ・システムは同じオペレーティングシステム(OS)を持たなければなりません。
B. キャプチャされたワークロードの数はマルチテナントCDB内のPDBの数と同じでなければなりません。
C. 複数のリプレイスケジュールは連結再生のために定義することができ、リプレイ初期化中に、既存のリプレイスケジュールのいずれかから選択することができます。
D. 取得したワークロードのサブセットが再生できます。
E. 複数のデータベースから複数のワークロードのキャプチャはマルチテナントコンテナデータベース(CDB)内のすべてのプラグイン可能なデータベース(PDB)で同時に再生することができます。
Answer: C,D,E
Explanation:
Explanation
These capture files are platform independent and can be transported to another system.
You can use Consolidated Database Replay to combine the captured workloads from the three applications and replay them concurrently on PDBs.
References:
https://docs.oracle.com/database/121/RATUG/GUID-36DE5567-5A64-493B-A154-6581C678FC8A.htm#RATU
https://docs.oracle.com/database/121/RATUG/GUID-42958859-005D-4B93-9DD3-79807968EA9E.htm#RATU
https://docs.oracle.com/database/121/RATUG/GUID-C4DC0795-74B2-456D-AA0A-B4F7F45C81F8.htm
https://docs.oracle.com/database/121/RATUG/GUID-B1AEA82F-60E5-43CE-BB12-C6D72232886A.htm


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