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NEW QUESTION: 1
NO: 203
Refer to the exhibit.
Which option is the result of this configuration?
A. Devices in OSPF area 0 can reach only the summary route of 192.168.0.0/16.
B. Devices in OSPF area 0 can reach the summary route 192.168.0.0/16 and its more specific subnets.
C. Devices in OSPF area 15 can reach only the more specific routes of 192.168.0.0/16.
D. Devices in OSPF area 15 can reach the summary route 192.168.0.0/16 and its more specific subnets.
Answer: D
Explanation:
- area range To consolidate and summarize routes at an area boundary, use the area range command in router configuration mode. To disable this function, use theno form of this command. Area area-id range ip-address mask [advertise | not-advertise] [cost cost] no area area-id range ip-address mask [advertise | not-advertise] [cost cost]
-Syntax Description
area-id
Identifier of the area about which routes are to be summarized. It can be specified as either a decimal value or as an IP address.
ip-address
IP address.
mask
IP address mask.
advertise
(Optional) Sets the address range status to advertise and generates a Type 3 summary link-state advertisement (LSA).
not-advertise
(Optional) Sets the address range status to DoNotAdvertise. The Type 3 summary LSA is suppressed, and the component networks remain hidden from other networks.
Reference: http://www.cisco.com/c/en/us/td/docs/ios/12_2/iproute/command/reference/fiprrp_r/1rfospf. html
NEW QUESTION: 2
A. SELECT COUNT(*)FROM (SELECT CustNoFROM tblDepositAcctUNIONSELECT
CustNoFROM tblLoanAcct) R
B. SELECT COUNT(*)FROM (SELECT AcctNoFROM tblDepositAcctINTERSECTSELECT AcctNoFROM tblLoanAcct) R
C. CustNo = L.CustNo
D. CustNo IS NULL
E. SELECT COUNT (DISTINCT COALESCE(D.CustNo, L.CustNo))FROM tblDepositAcct DFULL JOIN tblLoanAcct L ON D.CustNo = L.CustNoWHERE D.CustNo IS NULL OR
F. SELECT COUNT (DISTINCT D.CustNo)FROM tblDepositAcct D, tblLoanAcct LWHERE
G. SELECT COUNT(*)FROM (SELECT CustNoFROM tblDepositAcctEXCEPTSELECT
CustNoFROM tblLoanAcct) R
H. CustNo
I. SELECT COUNT(*)FROM tblDepositAcct DFULL JOIN tblLoanAcct L ON D.CustNo
J. SELECT COUNT(DISTINCT L.CustNo)FROM tblDepositAcct DRIGHT JOIN
tblLoanAcct L ON D.CustNo = L.CustNoWHERE D.CustNo IS NULL
K. SELECT COUNT(*)FROM (SELECT CustNoFROM tblDepositAcctUNION ALLSELECT CustNoFROM tblLoanAcct) R
Answer: B
Explanation:
The SQL INTERSECT operator is used to return the results of 2 or more SELECT statements. However, it only returns the rows selected by all queries or data sets. If a record exists in one query and not in the other, it will be omitted from the INTERSECT results.
References: https://www.techonthenet.com/sql/intersect.php
NEW QUESTION: 3
You need to update the Inventory API.
Which development tools should you use? To answer, select the appropriate options in the answer area.
NOTE: Each correct selection is worth one point.
Answer:
Explanation:
Explanation:
Scenario: The Inventory API must be written by using ASP.NET Core and Node.js.
Box 1: Entity Framework Core
Box 2: Code first
References:
https://docs.microsoft.com/en-us/aspnet/mvc/overview/getting-started/getting-started-with-ef-using-mvc/creating-an-entity-framework-data-model-for-an-asp-net-mvc-application
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