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NEW QUESTION: 1
You create a new database by using the CREATE DATABASEcommand in SQL *Plus, with the ENABLE
PLUGGABLE DATABASEclause specified.
Which statement is true about the database that is created?
A. It is created as a CDB with the CDB$ROOTand PDB$SEEDdatabases.
B. It is created as a non-CDB that becomes a CDB after the first PDB is plugged in.
C. It is created as a PDB that must be plugged into an existing CDB.
D. It is created as a container database (CDB) with CDB$ROOT, PDB$SEED, and a pluggable database
(PDB).
Answer: A
Explanation:
Explanation/Reference:
Explanation:
The CREATE DATABASE command with the ENABLE PLUGGABLE DATABASE clause indicates that a
CDB is being created. The CDB will contain a root (CDB$ROOT) and a seed (PDB$SEED).
References: https://docs.oracle.com/database/121/SQLRF/statements_5005.htm
NEW QUESTION: 2
You are project manager of HHK project. Examine the network diagram given below: A vendor reports that he will be four days late on the materials you'll need in order to complete Activity E.
Based on the project network diagram, how many days can Activity E be delayed?
A. Zero, it is on the critical path.
B. Five days
C. Four days
D. Six days
Answer: C
Explanation:
Activity E has four days of float. The entire project will take 19 days to complete. Float, also called slack, is the amount of time an activity can be delayed without affecting any subsequent activities. There are two types of floats available: Free Float: It is the amount of time a schedule activity can be delayed without delaying the early start date of any immediately following schedule activities. Total Float: It is the total amount of time that a schedule activity may be delayed from its early start
date without delaying the project finish date, or violating schedule constraint. Float is calculated by using the critical path method technique. Answer option D is incorrect. Activity E is not on the critical path. Answer options C and B are incorrect. These are incorrect calculations of the amount float available for Activity
E.
NEW QUESTION: 3
あなたはABC.comで開発者として働いています。
すべてのデータベースは、SQL Server 2012を実行しているWindows Server 2012サーバーでホストされています。
あなたはCorpCRMという名前のカスタムCRMアプリケーションを開発しています。
アプリケーションは、CorpCRMDB1という名前のSQL Server 2012データベースにユーザー名とパスワードを保存します。
ユーザー名とパスワードが安全であることを確認する必要があります。
次のうちどれが最も適切なパスワード保存ソリューションでしょうか？
A. 可逆暗号化
B. 暗号化ファイルシステム（EFS）
C. 一方向暗号化
D. Secure Sockets Layer（SSL）
Answer: C
NEW QUESTION: 4
Which two are true concerning the allocation ofi I/O resources by the IORM within the CELLSRV process?
A. Log Writer I/O to the Smart Flash Log is considered part ofi the SYSTEM resource consumer group by IORM.
B. Database Writer I/O is managed automatically at normal priority by IORM.
C. Control File I/O is considered part ofi the SYSTEM resource Consume group by IORM.
D. Control File I/O is managed automatically at high priority by IORM.
E. Log Writer I/O to the Smart Flash Log is managed automatically at high priority by IORM.
F. Database Writer I/O is considered part ofi the SYSTEM resource consumer group by IORM.
Answer: B,D
Explanation:
Note:
* IORM Rules
IORM is only "engaged" when needed.
/ (A) Redo and control file writes always take precedence.
/ (E) DBWR (database writer) writes are scheduled at the same priority as user IO.
/ IORM does not intervene ifi there is only one active consumer group on one database.
/ Any disk allocation that is not fiully utilized is made available to other workloads in relation to the configured
resource plans.
/ Background IO is scheduled based on their priority relative to user IO.
/ For each cell disk, each database accessing the cell has one IO queue per consumer group and three background
queues.
/ Background IO queues are mapped to "high", "medium", and "low" priority requests with different IO types mapped
to each queue.
/ Ifi no intradatabase plan is set, all non-background IO requests are grouped into a single consumer group called
OTHER_GROUPS.
Refierence: Using IORM with Exadata
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