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Vendor: Pegasystems

Exam Code: PEGACPLSA23V1 Dumps

Questions and Answers: 104

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NEW QUESTION: 1
You are proposing an Avaya Midsize solution with 200 agents, 10 supervisors, 225 non-agent UC users, and
200 non-agent Telephony users.
How many Telephony users and UC users would be Included In your Bill of Materials?
A. 200 Telephony users and 435 UC users
B. 210 Telephony users and 425 UC users
C. 410 Telephony users and 225 UC users
D. 400 Telephony users and 235 UC users
Answer: A

NEW QUESTION: 2
Click the Exhibit button.

You have deployed route reflectors in your network. You are receiving the route 200.0.0.0/24 from AS10 and AS6 and are seeing the oscillation happening as shown in the exhibit.
What are two ways to solve this issue? (Choose two.)
A. Configure the med-plus-igp parameter on both route reflectors.
B. Configure the add-path parameter on both route reflectors.
C. Configure the as-path-ignore parameter on both route reflectors.
D. Configure the always-compare-med parameter on both route reflectors.
Answer: A,D

NEW QUESTION: 3
Given the code fragment:
public class Test {
static String[][] arr =new String[3][];
private static void doPrint() {
//insert code here
}
public static void main(String[] args) {
String[] class1 = {"A","B","C"};
String[] class2 = {"L","M","N","O"};
String[] class3 = {"I","J"};
arr[0] = class1;
arr[1] = class2;
arr[2] = class3;
Test.doPrint();
}
}
Which code fragment, when inserted at line //insert code here, enables the code to print COJ?
A. int i = 0;
for (String[] sub: arr) {
int j = sub.length -1;
for (String str: sub) {
System.out.println(str[j]);
i++;
}
}
B. private static void doPrint() {
for (int i = 0;i < arr.length;i++) {
int j = arr[i].length-1;
System.out.print(arr[i][j]);
}
}
C. for (int i = 0;i < arr.length-1;i++) {
int j = arr[i].length-1;
System.out.print(arr[i][j]);
i++;
}
D. int i = 0;
for (String[] sub: arr[][]) {
int j = sub.length;
System.out.print(arr[i][j]);
i++;
}
Answer: B
Explanation:
Incorrect:
not A: The following line causes a compile error:
System.out.println(str[j]);
Not C: Compile erro line:
for (String[] sub: arr[][])
not D: Output: C


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