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Vendor: Certinia

Exam Code: PSA-Sysadmin Dumps

Questions and Answers: 104

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NEW QUESTION: 1
You are developing a SQL Server Integration Services (SSIS) package.
You need to design a package to change a variable value during package execution by using the least amount of development effort.
What should you use?
A. Script task
B. Expression task
C. Term Extraction transformation
D. Execute Process task
E. Execute SQL task
Answer: B
Explanation:
References:
http://msdn.microsoft.com/en-us/library/hh213137.aspx

NEW QUESTION: 2
Given:

What is the result?
A. The program prints nothing.
B. The compilation fails.
C. Orange Juice Apple Pie Lemmon Ice Raspberry Tart
D. Orange Juice
Answer: C
Explanation:


NEW QUESTION: 3
You are working for a company that designs mobile applications. They maintain a server where player records are assigned to their different games. The tracking system is new and in development.
The application uses Entity Framework to connect to an Azure Database. The database holds a Player table and Game table.
When adding a player, the code should insert a new player record, and add a relationship between an existing game record and the new player record.
The application will call CreatePlayerWithGame with the correct gameIdand the playerId to start the process.
(Line numbers are included for reference only.)

For each of the following statements, select Yes if the statement is true. Otherwise, select No.
NOTE: Each correct selection is worth one point.

Answer:
Explanation:

Explanation

Many-to-many relationships without an entity class to represent the join table are not yet supported. However, you can represent a many-to-many relationship by including an entity class for the join table and mapping two separate one-to-many relationships.
protected override void OnModelCreating(ModelBuilder modelBuilder)
{
modelBuilder.Entity<PostTag>()
HasKey(t => new { t.PostId, t.TagId });
modelBuilder.Entity<PostTag>()
HasOne(pt => pt.Post)
WithMany(p => p.PostTags)
HasForeignKey(pt => pt.PostId);
modelBuilder.Entity<PostTag>()
HasOne(pt => pt.Tag)
WithMany(t => t.PostTags)
HasForeignKey(pt => pt.TagId);
}
}


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